In a class of 15 students, there are 5 girls. in how many different ways can they be arranged in a row such that no two of the five girls are consecutive?
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total number of Students = 15 Students
and
NUmber of girls = 5 girls
thus
number of boys = 10
According to question
Ways in which they can be seated
= 10! X 5P2 X 5!
= 10 * 9 * 8 * 7 * 6 * 10
= 302400
and
NUmber of girls = 5 girls
thus
number of boys = 10
According to question
Ways in which they can be seated
= 10! X 5P2 X 5!
= 10 * 9 * 8 * 7 * 6 * 10
= 302400
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