in a class of 150, where girls are twice the number of boys. Riyan (a boy) ranked 41st from the top. If there are 19 girls ahead of Riyan, how many boys are after him in rank?
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Answered by
2
Answer:
riyan's rank = 41st
students ahead of him = 40
girls ahead of him = 19
therefore boys ahead of him = 40-19=21
150=50+50+50
no.of girls is twice the no.of boys...
therefore no.of girls = 50+50=100
no.of boys= 50
boys ahead of him= 21
riyan himself is a boy
so no.of boys ahead of riyan including him= 22
no.of boys ranked after him= 50-22= 28
Answered by
1
Answer:
150 - total
100- girls
50- boys
Rayan- 41
girls ahead Rayan-19,
then boys before Rayan 21
boys till 41- 21+1(including rayan)
50-22= 28
answer - 28
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