Question

in a class of 20. 8 read math and 13 read English how many students with both English and maths​

Answer 1

Answer:

Maths - M

English - E

Total students (M U E) = 20

n(M) = 8

n(E) = 13

Now,

n(M intersection E)= n(M) + n(E) - n(M U E)

= 8+13-20

= 21-20

= 1

Answer 2

Answer:

1

20 = 8+13-(common)