Question

In a class of 40, 15 students opt for Sanskrit. The rest opt for French or German. If the probability that a student selected at random studies French is 2/5, find the number of students who opted for French. Also, find the probability that a student selected at random studied German.​

Answer 1

Answer:

32 opted for french

Step-by-step explanation:

Answer 2

Answer:

16 students opted for French.

P(of selecting a German opted student) = 9/40

Step-by-step explanation:

We know that,

Class strength is 40, out of which 15 opted for Sanskrit and the rest for French or German.

Now,

If 15 students opted for Sanskrit, the rest of the students = 40 - 15 = 25 students,

Thus, 25 students either opted for French or German,

Let x be the students who opted for French, and y be the students who opted for German.

Thus,

x + y = 25 ------ 1

Now,

The probability of selecting a student who opted French = No. of Students opted for French/Total students

= x/40

But we are given that the probability is 2/5 thus, they must be equivalent.

∴ x/40 = 2/5

x = (2/5) × 40

x = 2 × 8

x = 16 students

Thus, 16 students opted for French.

Now, from eq.1 we get,

16 + y = 25

y = 25 - 16

y = 9

Hence, 9 students opted for German.

Thus, Probability of selecting a student who has opted for German = Sudents of opted for German/Total students.

Thus,

P(of selecting a German opted student) = 9/40

Hope it helped and you understood it........All the best.