Question

In a class of 40 students, each one plays either tennis or badminton or both. If 28 play tennis and 26 play badminton, find (i) how many play both the games ;(ii) how many play tennis only; (iii) how many play badminton only.​

Answer 1

i) both games playing students =28+26 =54 students

i i) players only play tennis = 28

iii) students only play badminton = 26

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Answer 2

Answer:14 play both, 14 play tennis and 12 play badminton

Step-by-step explanation:

26 - x + x + 28 - x = 40

- x + x - x = 40 - 28 -26

- x = - 14

Play both x = 14

Tennis = 28 - x

= 28 -(14)

= 14

Badminton = 26 - x

= 26 - (14)

= 12