Question

In a class of 400 students, 10% participate in dance program, 8% participate in

English play, 4% in Hindi play, 20% in music program. How many of the

students do not take part in any activity?​

Answer 1

Step-by-step explanation:

Total percentage of participants=(10+8+4+20)%=42%

The percentage of participants who didn't take part any activity = (100-42)% =58

So the number of students who didn't take part in any activity

=400of58%

=400×58/100

=4×58

=332

So the 332 students do not take part in any activity.

Hope it helps you...

Answer 2

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• Class consists of 400 students.

• 10% participated in dance program.

• 8% parricipated in english play.

• 4% parricipated in hindi play.

• 20% participated in music program.

$\\ \\ \large\underline{ \underline{ \sf{ \red{to \: find:} }}}$

• Number of students who do not participated in any activity.

$\\ \\ \large\underline{ \underline{ \sf{ \red{solution:} }}}$

We have 100% of students.

→ % of students not participated = Total % of student - % of students participated

→ % of students not participated = 100 - (10+8+4+20)

→ % of students not participated = 100-42

→ % of students not participated = 58

Hence , 58% of students did not participated in any of the programs.

We have to find 58% of 400.

$\\ \implies \sf \: \frac{58}{ \cancel{100}} \times \cancel{ {400}} \: \: ^{4} \\ \\ \implies \sf \: 58 \times 4 \\ \\ \implies \sf \: 232$

Hence , 232 students didnt participated in any activity.