Question

In a class of 48 students regular students are mire than irregular students had 2 irregular students been regular the product of the number of 2 types of students would be 380 find the number of students of each type

Answer 1

• number of students=48

• regular students be x

• irregular students=48-x

when 2 irregular became regular

• reg students=x+2

• num of irreg students=48-x-2=46-x

product of both is 380

(x+2)*(46-x)=380

middle term break

(x-36)(x-8)=0

so x can be

36 or 8

as reg students are more than irre students so x=36

number of irregular=48-x=48-36=12