Question

in a class of 50 boys, 35 boys play carrom and 20 boys plays chess then the number of boys play both games is what? ​

Answer 1

Answer:

5 number of boys playing the both game .

there are 50 boys 20 play chess 35 play carrom .

In this the 5 are common....

Answer 2

Answer:

The number of boys playing both games is 5.

Step-by-step explanation:

Given,

In a class of 50 boys, 35 boys play carrom and 20 boys play chess.

To find,

A number of boys play both games.

Step 1

$&n(A \cup B)=50$

n(A)=35

n(B)=20

$&n(A \cap B)=n(A)+n(B)-n(A \cup B)$

$&=35+20-50$

$&=5$

The number of boys playing both games is 5.

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