Question

In a class of 50 students, 10 have failed and their average marks is 28. The total marks obtained by the entire class are 2800. The average marks of those who have passed are

Answer 1

The average marks of those who have passed are 63

Solution:

Total students = 50

Failed = 10

Then, passed = 50 - 10 = 40

The average is given as:

$Average = \frac{ \text{ sum of marks }}{ \text{ total number of students }}$

Given that,

10 have failed and their average marks is 28

Total marks of 10 failed students = 10 x 28 = 280

Total marks of 50 students = 2800

Therefore,

Total marks of 40 passed students = 2800 - 280 = 2520

Find the average of passed students

$Average = \frac{2520}{40} = 63$

Thus the average marks of those who have passed are 63

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Answer 2

Solution-:

Given -:

In a class no of students = 50

failed students= 10

Average mark = 28

total mark obtained = 2800

To find -:

The average marks of those who have passed are?

Required Answer -:

The average marks of those who have passed are 63

Let's Begin -:

$\large{ \sf{total \: number \: of \: stu. \: passed \: = 50 - 10 = 40}}$

$\large{ \sf{total \: mark \: obtained \: by \: failed \: student}}$

$\large{ \sf{ = 28 \times 10 = 280}}$

$\large{ \sf{total \: mark \: of \: 40 \: stud. = 2800 - 280 = 2520}}$

$\large{ \sf{required \: average \: of \: passed \: stu.}}$

$\large{ \sf{ \green{ \frac{2520}{40} = 63 \: ans}}}$

The average marks of those who have passed are 63 answer