In a class of 50 students, 28 opted for NCC ,28 opted for NSS and, 10 opted for both NCC
and NSS. One of the students is selected at random. Find the probability
ed for NCC but not NSS (ii) The Student opted for
his is selected at random. Find the probability that (i) the student opted for NCC but not NSS (2) the student opted for NSS but not NCC (3) the student opted for exactly one of them
Answers
Given : In a class of 50 students, 28 opted for NCC ,28 opted for NSS and, 10 opted for both NCC and NSS. One of the students is selected at random.
To Find : the probability
(i) the student opted for NCC but not NSS
(2) the student opted for NSS but not NCC
(3) the student opted for exactly one of them
Solution:
Total = 50
NCC = 28
NSS = 28
BOTH = 10
NONE = ?
Total = NCC + NSS - BOTH + NONE
=> 50 = 28 + 28 - 10 + NONE
=> NONE = 4
ONLY NCC = NCC - BOTH = 28 - 10 = 18
ONLY NSS = NSS - BOTH = 28 - 10 = 18
Opted exactly one of them = 18 + 18 = 36
probability that (i) the student opted for NCC but not NSS = 18/50
= 0.36
probability that (i) the student opted for NSS but not NCC = 18/50
= 0.36
probability that the student opted for exactly one of them = 36/50
= 0.72
Learn More:
In a class of 140 students, 60 play football, 48 play hockey and 75 ...
https://brainly.in/question/9857890
50 students of a class like either oranges or grapes or both. 20 of ...
https://brainly.in/question/13834831
Step-by-step explanation:
Probabilities are 0.2,0.24,0.44 respectively.
Total no of students = 50
No of students opted for NCC = 28
No of students opted for NSS = 30
No of students opted for both = 18
Therefore,
No of students opted for NCC only = 28-18 = 10
No of students opted for NSS only = 30-18 = 12
(i) the probability that the selected student opted for NCC but not NSS = 10/50 = 0.2
(ii) the probability that the selected student opted for NSS but not NCC = 12/50 = 0.24
(iii) the probability that the selected student opted for exactly one of them = (10+12)/50 = 22/50 = 0.44