Math, asked by abhisheksomugomu1020, 11 months ago

In a class of 50 students, 28 opted for NCC, 30 opted for NSS and 18 opted for NCC and
NSS. One of the students is selected at random. Find the probability that
(i) the selected student opted for NCC but not NSS
(ii) the selected student opted for NSS but not NCC
(iii) the selected student opted for exactly one of them.(please any one say the page no of this question in 10th maths book)

Answers

Answered by qwfun

Probabilities are 0.2,0.24,0.44 respectively.

Therefore,

(i) the probability that the selected student opted for NCC but not NSS = 10/50 = 0.2

(ii) the probability that the selected student opted for NSS but not NCC = 12/50 = 0.24

(iii) the probability that the selected student opted for exactly one of them = (10+12)/50 = 22/50 = 0.44

Answered by amitnrw

Given : In a class of 50 students, 28 opted for NCC, 30 opted for NSS and 18 opted for NCC and NSS

To find : the probabilities if one students is selected at random

Solution:

Total Students = 50

NCC = 28

NSS = 30

Opted for Both = NCC ∩ NSS = 18

opted for None = ?

50 = 28 + 30 - 18 + none

=> none = 10

10 opted for none

Opted for NCC but not NSS = NCC - (NCC ∩ NSS)

= 28 - 18

= 10

Probability = 10/50 = 1/5

opted for NSS but not NCC = NSS - (NCC ∩ NSS)

= 30 - 18

= 12

Probability = 12/50 = 6/25

student opted for exactly one of them = 10 + 12 = 22

Probability = 22/50

= 11/25

1/5 Opted for NCC but not NSS

6/25 opted for NSS but not NCC

11/25 opted for exactly one of them

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