In a class of 50 students, each of the students passed either in mathematics or in science or in both. 10 students passed in both and 28 passed in science. Draw a Venn diagram and state how many students:
Passed science but not mathematics Failed science Passed mathematics Failed both subjects
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Heyaa♡♡
Let M= The set of students passed in Mathematics.
S= The set of students passed in Science
Then, n(S)=28,n(M∩S)=10,n(M∪S)=50
We have n(M∪S)=n(M)+n(S)−n(M∩S)
50=n(M)+28−10
50=n(M)+18
⇒n(M)=32
Aliter
From the Venn diagram
x+10+18=50
x=50−28
x=22
Number of students passed in Mathematics =
x+10=22+10=32
Hope it helped you.
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