Question

IN A CLASS of 50 students following is the distribution of the 2nd language opted by the students : sanskrit - 14 , japanese - 08 , french - 12 , urdu - 6 and rest of them opted for german, a student is selected at random. Find the probability that the student (a) opted for french (b) does not opt for japanese (c) either opt for sanskrit or german ? ( PLS GIVE ANS URGENTLY, SIR WITH DETAILED EXPLANATION)

Answer 1

given there are 50 students ,
so for probabitlity we do
favorable/total
a) opted a french= 12/50=0.24=24/100[if want solve]

b)doesn't japanease means except japanease
so 50-8=42
probability is 42/50=0.84=84/100 [ if want solve]
c) either sanskrit or geman means except sansrit and german
first we have to find german=?
so, 40-50=10
german = 10
now sanskrit+german+14+10=24
so given either sansrit or german so 24-50=26
probability=26/50=0.52=52/100[if want solve]

Answer 2

Answer:

I) no. of students opted for French n (E)= 12

total no. of outcomes n (S)=50

probability of student opted for french P (E)=n (E)/n (S)=12/50 = 6/25

ii) probability of students opted gor Japanese P (E1)= 8/ 50=4/25

So tge probability of student not opted for Japanese= 1- P (E1)= 1- 4/25=21/25

iii) no. of favourable outcomes n (E2) =10+14= 24

P (E2)= 24/50= 6/2