Question

In a class of 50 students who offer either mathematics or account or both,20 offer mathematics and 40 offer account.How many offer both subjects and how many offer only mathematics only? Represent the above information in an Venn-diagram.(Ans=10,10)
=)Plz give me the process how to solve it.

Answer 1

Answer:

it's really easy just to draw a circle and draw a line in the circle one side write mathematics and another side account

Answer 2

Given:

In a class of 50 students who offer either mathematics or account or both, 20 offer mathematics and 40 offer account.

To find:

How many offer both subjects and how many offer only mathematics only?

Represent:

The above information in an Venn-diagram

Solution:

Let M = the set of students who offer mathematics.

A = the set of students who offer accóunts

Then,

n(M) = 20

n(A) = 40

n(M ∪ A) = 50

We have,

n(M ∪ A) = n(M) + n(A) - n( M ∩ A )

50 = 20 + 40 - n( M ∩ A )

50 + n( M ∩ A ) = 60

n( M ∩ A ) = 60 - 50

n( M ∩ A ) = 10

Refer the attachment!!

━━━━━━━━━━━━━━━━━━━━━