in a class of 56 students the number of boys is two fifth of the number of girls find the number of boys and girls
Answers
Answered by
30
hey
here is your answer !!
______________
let the number of girls be x
then no of boys = 2/5x
now according to the question
as we know total students are 56
so
x + 2/5x = 56
7x / 5 = 56
x = 56 * 5 / 7
x = 40
hence the number of girls is 40
then no of boya r 2/5 * 40 = 16
or ( 56 - 40) = 16
----------------------------
hope it helps :)
here is your answer !!
______________
let the number of girls be x
then no of boys = 2/5x
now according to the question
as we know total students are 56
so
x + 2/5x = 56
7x / 5 = 56
x = 56 * 5 / 7
x = 40
hence the number of girls is 40
then no of boya r 2/5 * 40 = 16
or ( 56 - 40) = 16
----------------------------
hope it helps :)
Answered by
34
Total number of student = 56
Let the number of Girls be = x
Then number of boys will be= 2/5 x.
According to question:-
x+2/5 x = 56
(5/5)x+ (2/5)x = 56 {by taking LCM}
(7/5)x = 56
7x = 56×5
x = 56×5/7
x = 8×5 {56 is divided by 7}
x = 40
So, number of girls = x
= 40
Number of boys = 2/5 × x
= 2/5 × 40
= 2 × 8
= 16
Hope it helps.
Let the number of Girls be = x
Then number of boys will be= 2/5 x.
According to question:-
x+2/5 x = 56
(5/5)x+ (2/5)x = 56 {by taking LCM}
(7/5)x = 56
7x = 56×5
x = 56×5/7
x = 8×5 {56 is divided by 7}
x = 40
So, number of girls = x
= 40
Number of boys = 2/5 × x
= 2/5 × 40
= 2 × 8
= 16
Hope it helps.
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