in a class of 60 boys there are 45 boys who play card and 30 boys who play carrom. also each boy likes to play atleast one game .use set operation to find!
Answers
Answered by
13
Hey mate here is your answer⤵⤵⤵
the answer is 40 boys.
✔✔Explanation✔✔
Let's say there are x boys who play both cards and carrom.
We setup up an equation that involved all information given and x.
Boys who only play cards = 45-x
Boys who only play carrom = 20-x
Boys who play both = x
Add there together and you should get 60, which is the total number of students in the class.
(45-x)+(20-x)+x=60
65-x=60
x=5
Boys who only play cards=45-x=45–5=40
hope it helps you
Please mark as BRAINLIEST.
the answer is 40 boys.
✔✔Explanation✔✔
Let's say there are x boys who play both cards and carrom.
We setup up an equation that involved all information given and x.
Boys who only play cards = 45-x
Boys who only play carrom = 20-x
Boys who play both = x
Add there together and you should get 60, which is the total number of students in the class.
(45-x)+(20-x)+x=60
65-x=60
x=5
Boys who only play cards=45-x=45–5=40
hope it helps you
Please mark as BRAINLIEST.
Answered by
20
No of boys who play both cards and carrom = x
no of boys who play cards = 45 -x
No of boys who play carroms = 30 - x
total boys = 60
45- x + 30 - x + x = 60
75 - x = 60
x = 75 -60 = 15
No of boys who play both cards and carrom = 15
no of boys who play cards = 45 -15 = 30
No of boys who play carroms = 30 - 15 = 15
or (easy one)
Children who play cards and carroms = 45 + 30 = 75
No of total children = 60
so children play both card and carrom = 75 - 60 =15
no of boys who play cards = 45 -15 = 30
No of boys who play carroms = 30 - 15 = 15
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