in a class of 60 students 25 play cricket 20 students play tennis and 10th students play both the game the number of students who play neither tennis nor cricket is
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Answered by
96
no of students U = 60.
student who play cricket C = 25.
student who play tannis T = 20.
students who plays both of them = 10
so student who plays neither of them = 60 - ( 25+ 20 - 10 ) = 60 - 35 = 25
student who play cricket C = 25.
student who play tannis T = 20.
students who plays both of them = 10
so student who plays neither of them = 60 - ( 25+ 20 - 10 ) = 60 - 35 = 25
Answered by
70
Answer:
Number of students who play neither tennis nor cricket is 25.
Step-by-step explanation:
Let U be the universal set that is collection of all students, n( U ) = 60
C be the set of student play cricket , n( C ) = 25
T be the set of student play tennis , n( T ) = 20
number of students who play both game , n( C ∩ T ) = 10
We need to find number student who don't play any game, n( C ∪ T )'
we know that,
n ( C ∪ T ) = n( C ) + n( T ) - n( C ∩ T )
= 25 + 20 - 10
= 45 - 10
= 35
n( C ∪ T )' = n( U ) - n( C ∪ T ) = 60 - 35 = 25
Therefore, Number of students who play neither tennis nor cricket is 25.
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