Question

In a class of 60 students; 30 selected for NCC,
32 selected for NSS and 24 selected both
NCC and NSS. If one of these students is
selected at random, find the probability that:
i) the student selected for NCC or NSS. ii) the student has selected neither NCC nor
NSS.

Answer 1

i)let students selected for NCC be A

let students selected for NSS be B

NCC or NSS be n(AUB)

NCC and NSS both be n(AintersectionB)

U be 60

n(AUB)= n(A)+n(B)-n(A intersection B)

=30+32-24

=62-24

=38

n(AUB)'=n (U)-n(AUB)

=60-38

=22

Therefore, answer is

i)38 students

ii)22 students

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Answer 2

Answer:

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