Question

in a class of 60 students 45 play cricket 40 play football and 5 play nothing,find how many students play both games​

Answer 1

Answer:

given number of universal set = 60

let

number of cricket playing student = n(c)

no. of football paying student = n(f)

no. of students who play both = n(cnf)

no. of students who play atleast one = n(cuf)

now.

n(cuf) = 60 - 5 = 55

we know that

n(cuf) = n(c) + n(f) - n(cnf)

55 = 45 + 40 - n(cnf)

n(cnf) = 85 - 45

= 40