Question

In a class of 60, where girls are twice that of boys, Amal ranked seventeenth from the top. If there are 9 girls ahead of Amal, how many boys are after him in rank ?

Answer 1

Answer:

Step-by-step explanation:

Let the number of boys be x.  Then, numbers of girls = 2x.

.'. x + 2x = 60  or  3x = 60  or  x = 20.

 

So, number of boys = 20 and numbers of girls = 40.

Number of students behind Kamal in rank = (60 - 17) = 43.

Number of girls ahead of Kamal in rank = 9.

Number of girls behind Kamal in rank = 40 - 9 = 31.

.'. Number of boys behind Kamal in rank = 43 - 31 = 12

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