Math, asked by Kamaan1516, 9 months ago

In a class of 75 students ,where boys are twice that of girls .Dhanuja ranked thirteenth from top.if there are four girls ahead of dhanuja ,how many boys are after her in rank?

Answers

Answered by saikharpandey3127
6

Answer:

42

Step-by-step explanation:

let the no. of girls be x

no. of boys= 2x

2x+x=75

3x=75

x=25

No. of boys= 50

Answered by ankhidassarma9
0

Answer:

The number of boys after Dhanuja in the ranking order is 42.

Step-by-step explanation:

  • Total number of Student in the class is 75.
  • Let the number of girls in the class be x.

    so, the number of boys in the class is twice of x ,i.e. 2x.

  • no. of boys + no. of girls = Total no. of students

    so, we can write 2x + x = 75

                           3x = 75

                            x  = 25

                   hence x = 25 and 2x = 50

  • The number of girls in the class is 25.

       The number of boys in the class is 50.

Dhanuja is ranked 13th from the top. If there are 4 girls ahead of Dhanuja, then there must be 8 boys ahead of Dhanuja so that Dhanuja can hold 13th position.

Hence, till 13th position 5 girls (including Dhanuja) are there.

so, number of boys after Dhanuja = 50 - 8 =42.

The number of boys after Dhanuja in the ranking order is 42.

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