In a class of 80 students numbered a to 80, all odd
numbered students opt of Cricket, students whose
numbers are divisible by 5 opt for Football and those
whose numbers are divisible by 7 opt for Hockey. The
number of students who do not opt any of the three
I
games, is
(a) 13
(C) 28
(b) 24
(d) 52
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Step-by-step explanation:
Correct option is
Correct option isC 28
Here, n(C)=40, n(F)=16, n(H)=11, n(C∩F)=8, n(C∩H)=6, n(F∩H)=2, n(C∩F∩H)=1
⇒n(C∪F∪H)=40+16+11−8−6−2+1=52
⇒n(C
′∩F
∩H
=n(U)−n(C∪F∪H)
=80−52=28
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