Question

In a class of (8ax² – 2bx + 10t – 4) students, (4ax² + 7bx – 9t + 6 ) are boys. How many girls are there? *

4ax² – 9bx + 19t -10

4ax² – 8bx + 19t -10

4ax² – 9bx + 19t -11

4ax² – 8bx + 18t -11

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Answer 1

Answer:

4ax² – 9bx + 19t -10......

Answer 2

Step-by-step explanation:

4ax² – 9bx + 19t -10.........