Question

In a class of 90 students, where girl are twice that of boys, ajay ranked fourteenth from the top.if there are 10 girl Ahead of ajay, how many boys are after him in rank?

Answer 1

Answer:

LET the boys be x.

tHEn the girls= 2x

ATQ,

Total students=90

So,x+2x= 3x= 90

X = 90/3 =20.

He ranks fourteen and 10 girls are above him means 3 boys are above him.

boys after him in rank=20-4=16

Answer 2

Answer:

Concept:

Time sequence, timing, and ranking in Reasoning

Explanation:

Given:

Total Class = 90 students

Girls are twice that of boys

Ajay ranked 14th from top

10 girls ahead of ajay

Find:

how many boys are after ajay

Solution:

$\begin{gathered}{B}+{G}=90 \\x+2 x=90 \\3 x=90 \\x=\frac{90}{3}=30\end{gathered}$

So, Boys = 30

     Girls  = 60

As ajay is in 14th rank, 13 students will be there before him,

Girls  ahead ajay are 10 i.e., 13 - 10 = 3 boys

Ajay + 3 boys = 4 boys

Total boys - 4 boys = 30 - 4 = 26

so 26 boys are after him in rank.

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