Question

in a class of1000 student 625 students pass in mathematics and525 pass in english.How many students pass in mathematics only And how many students pass in English only​

Answer 1

Step-by-step explanation:

total students passed =525+ 625= 1150

total students=1000

no of students passed in both subjects=1150 -1000= 150

Answer 2

Concept Introduction:-

It may be in the form of a word, a symbol, or a figure that reflects the arithmetic value of a quantity.

Given Information:-

We have been given that in a class of $1000$ students $625$ students pass in mathematics and $525$ pass in English.

To Find:-

We have to find that students pass in mathematics only and English only

Solution:-

According to the problem

Let, M be the set of students who passed in mathematics and E be the set of students who passed in English.

Total number of students$=n(M \cup E)=1000$

Number of students who passed in Mathematics$=n(M)=625$

Number of students who passed in English$=n(E)=525$

Number of students who passed both Mathematics and English$=n(M \cap E)$

$\begin{aligned}&\Rightarrow \mathrm{n}(\mathrm{M} \cup \mathrm{E})=\mathrm{n}(\mathrm{M})+\mathrm{n}(\mathrm{E})-\mathrm{n}(\mathrm{M} \cap \mathrm{E}) \\&\Rightarrow 1000=625+525-\mathrm{n}(\mathrm{M} \cap \mathrm{E}) \\&\Rightarrow \mathrm{n}(\mathrm{M} \cap \mathrm{E})=1150-1000\\&\Rightarrow \mathrm{n}(\mathrm{M} \cap \mathrm{E})=150\end{aligned}$

Number of students passed in Mathematics$=625$

Number of students passed in Mathematics and English both$=150$

∴Number of students passed only in Mathematics$=625-150=475$

Number of students who passed in Mathematics$= n(M)=475$

Number of students who passed in English$= n(E)=525-150=375$

Final Answer:-

The number of students who passed in Mathematics and English only are $475$ and $375$ respectively.

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