in a class of26 students 8 take tea but not coffee 16 take tea only how many take coffee but not tea.( by sets formula)
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T=26n
(t)=8
(t interaction c)=16
(t union c)=2
Therefore n(c)=?
n(c)=n(t union b)+n(t interaction c)-n(t)
n(c)=2+16-8
=2+8
=10
(t)=8
(t interaction c)=16
(t union c)=2
Therefore n(c)=?
n(c)=n(t union b)+n(t interaction c)-n(t)
n(c)=2+16-8
=2+8
=10
afifa2:
thank u for answering
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