Question

In a class test, the sum of Shefali’s marks in Mathematics and English is 30. Had she got 2 marks more in Mathematics and 3 marks less in English, the product of her marks would have been 210. Find her marks in two subjects.

Answer 1

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Let ,

Shefali got in math= x number

.°. in English = 30 - x number

A/Q,

( x + 2 ) ( 30 - x - 3 ) = 210

=> ( x + 2 ) ( 27 - x ) = 210

=> 27x - x² + 54 - 2x = 210

=> - x² + 25x + 54 = 210

=> - x² + 25x - 156 = 0

=> x² - 25x + 156 = 0

here a = 1 , b= - 25 , c= 156

.°. x = - ( -25 ) ± √(-25)² - 4 × 1 × 156/ 2 × 1

= 25 ± √625 - 624/ 2

= 25 ± √1/ 2

= 25 ± 1 /2

.°. x = 25+1/2 and 25 - 1/2

= 13 and 12

while x = 13

shefalis math number is = 13

and English number is = 30 - 13 = 17

when

x = 12

shefalis math number is = 12

and English number is = 30 - 12 = 18

hope!!...it helps uhh...❣️

Answer 2

Answer:

Step-by-step explanation:

Solution :-

Let the marks in Mathematics be x.

And the marks in English will be 30 - x.

According to the Question,

⇒ (x + 2)(30 - x - 3) = 210

⇒ (x + 2)(27 - x) = 210

⇒ - x² + 25x + 54 = 210

⇒ x² - 25x + 156 = 0

⇒ x² - 12x - 13x + 156 = 0

⇒ x(x - 12) -13(x - 12) = 0

⇒ (x - 12)(x - 13) = 0

⇒ x = 12, 13

If x = 12, then

Marks in Mathematics = x = 12

Marks in English = 30 - x = 30 - 12 = 18

If x = 13,then 

Marks in Mathematics = x = 13

Marks in English = 30 - x = 30 - 13 = 17