In a class test, the sum of the marks obtained by P in mathematics and science is 28. Had he got 3 more marks in mathematics and 4 marks less in science, the product of marks obtained in the two subjects would have been 180. Find the marks obtained by him in the two subjects separately.
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Answered by
6
Let the marks in maths be x.
Then, the marks im science will be 28-x.
According to the question,
(x+3) (28-x-4) = 180
(x+3) (24-x) =180
24x-x^2+72-3x = 180
21x-x^2+72 = 180
x^2-21x+108 =0
x^2-(12+9)x+108=0
x^2 - 12x-9x+108=0
x(x-12) - 9(x- 12)=0
(x-12) (x-9) =0
x = 12 x= 9
If the marks in maths =12
Then marks in science = 16
If the marks in maths =9
Then marks in science= 19...
I hope it helps u.....
Then, the marks im science will be 28-x.
According to the question,
(x+3) (28-x-4) = 180
(x+3) (24-x) =180
24x-x^2+72-3x = 180
21x-x^2+72 = 180
x^2-21x+108 =0
x^2-(12+9)x+108=0
x^2 - 12x-9x+108=0
x(x-12) - 9(x- 12)=0
(x-12) (x-9) =0
x = 12 x= 9
If the marks in maths =12
Then marks in science = 16
If the marks in maths =9
Then marks in science= 19...
I hope it helps u.....
Answered by
2
Let the marks obtained by him in maths be x and in science be y
X+y=28......y=28-x....i
(X+3)(y-4)=180
Xy-4x+3y-12=180
Xy-4x+3y-192=0
Subs i,
X(28-x)-4x+3(28-x)-192=0
28x-x^2-4x+84-3x-192=0
X^2-21x+108=0
On solving u wll get the value of x as 12 or 9
On sub it in i,y=16 or 19
X+y=28......y=28-x....i
(X+3)(y-4)=180
Xy-4x+3y-12=180
Xy-4x+3y-192=0
Subs i,
X(28-x)-4x+3(28-x)-192=0
28x-x^2-4x+84-3x-192=0
X^2-21x+108=0
On solving u wll get the value of x as 12 or 9
On sub it in i,y=16 or 19
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