Question

In a class, the highest score is 91. If the highest score is twice the
lowest score plus 11, find the lowest score.​

Answer 1

Answer:

The lowest score of the exam was 40.

Step-by-step explanation:

It is provided that the highest score is twice the  lowest score plus 11.

The statement can be expressed as follows:

      Highest score = (2 × Lowest score) + 11

                          91 = (2 × Lowest score) + 11

(2 × Lowest score) = 91 - 11

       Lowest score = 80/2

                               = 40

Thus, the lowest score of the exam was 40.

Answer 2

Answer:40

Step-by-step explanation:

higher score is 91

lowest score is = 2*lower score+11

                 higher score = 2*lower score+11

                                   91 = 2*lower score+11

                                   80 = 2*lower score

                  lower score = 40