Question

In a class, the number of boys is 8 less than that of girls. If the total number of boys and girls of that class is 48, find the number of boys and number of girls

Answer 1

let the no. of girls =x
then no. of boys =x-8....
given total no. of boys and girls=48
x+x-8=48
2x-8=48
2x=56
x=28..
therefor no. of girls =28 and boys=28-8=20....
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Answer 2

We can write this situation in the form of a linear equation with two variables. We can take 'b' to represent boys and 'g' to represent girls. So-

$b=g-8\\b-g=-8$

This is our first equation. The second equation will be as follows-

$b+g=48$

So, now, we can add both the equations together, to obtain the value of boys and girls-

$(b-g) + (b+g) = -8+48\\2b=40\\b=20$

So the number of boys is 20. We can substitute 20 into the second equation-

$b+g=48\\20+g=48\\g=28$

Thus, the number of boys is 20 and the number of girls is 28.