Question

in a class the number of girls is 20% more then that of the boys . the strength of the class is 66 . if 4 more girl are admitted to the class. what will be the ratio of the number of boys to the girls

Answer 1

consider number of boys in the class = x.

so, number of girls will be = x + (x*(20/100)) = 6x/5

Girls:boys = 6:5;

Hence, girls = 6*66/11 = 36;

Boys = 30;

New ratio, 30:(36+4) = 3:4.

Answer 2

The ratio of the number of boys to the girls is 3 : 4

Solution:

Let the number of boys in class be "b"

Let the number of girls in class be "g"

Given that the strength of the class is 66

So, we can frame as,

b + g = 66  ----- eqn 1

Also given that number of girls is 20% more than that of the boys

So we can say,

number of girls = number of boys + 20 % of boys

$g = b + 20\% \text{ of } b\\\\g = b + \frac{20}{100} \times b\\\\g = b + \frac{b}{5}\\\\g = \frac{6b}{5}$

Substitute the above value of g in eqn 1

$b + \frac{6b}{5} = 66\\\\5b + 6b = 66 \times 5\\\\11b = 66 \times 5\\\\b = 6 \times 5 = 30$

Therefore number of boys in class is 30

From eqn 1,

b + g = 66

30 + g = 66

g = 36

Therefore number of girls in class is 36

Now if 4 more girl are admitted to the class,

then number of girls = 36 + 4 = 40

New ratio is given as:

b : g = 30 : 40

Reducing to lowest form we get,

b : g = 3 : 4

Thus the ratio of the number of boys to the girls is 3 : 4

Learn more about ratios

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Out of 50 students in a class, 30 are boys. Find the ratio of

(i) number of boys to the number of girls.

(ii) number of girls to the total number of students.

(iii) number of boys to the total number of students.

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