Question

In a class there are 10 students who play football and cricket, 7 students who do not play football or cricket, 14 students who play football, 21 students who play cricket, Find the probability that a student chosen at random plays football and cricket

Answer 1

Answer:

here's the answer of your question, grab it

Step-by-step explanation:

GIVEN -

NUMBER OF STUDENTS WHO PLAY FOOTBALL AND CRICKET - 10

NUMBER OF STUDENTS WHO DO NOT PLAY FOOTBALL OR CRICKET - 7

NUMBER OF STUDENTS WHO PLAY FOOTBALL-

14

NUMBER OF STUDENT WHO PLAY CRICKET - 21

let's find the probability of a student chosen at random who plays football and cricket

FORMULA -

$probability = outcome number \div total number$

Outcome number = 10

Total number = 52

so probability will be -

$= \frac{10}{52}$

➡️____THANKS____⬅️

Answer 2

Answer:

5/16

Step-by-step explanation

14-10=4 only football

21-10=11 only cricket

Probability= 10 / (10+7+4+11)= 10/32 which can be simplified to 5/16