Question

In a class there are 14 boys and 10 girls. If one child is absent, the probability that it is a boy is(A) $\frac{5}{12}$(B) $\frac{7}{12}$(C) $\frac{10}{14}$(D) $\frac{1}{3}$

Answer 1

P(child absent is a boy) =10/24

=5/12

Answer 2

Answer:

7/12

Step-by-step explanation:

Total boys = 14

Total children = 24

So, the probability is 7/12