Question

In a class there are 25 males and 20 females. What is the probability of selecting 4 males and 5 females?

Answer 1

Answer:

for male:-

p(E)=Male/ total no of people

=4/45

:-probability of Male = 4/45

for female:-

p(E)=female/ total no of people

=5/45

=1/9

:-probability of female = 1/9

Answer 2

Answer:

The probability of selecting 4 males and 5 females is 0.22

Step-by-step explanation:

Given:

The number of males is 25  Number of females is 20  Number of the selected student at random is 4males and 5 females

Calculation:

Let S be the sample space and E be the event of selecting 4 males and 5 females.

Then, n(S)= The number ways of selecting 9 students out of 45

= $45{_C} 9$

$= 886,163,135\\n(E) = (25C4 * 20C5)\\=12650 * 15,504\\ =19,61,25,600$$P(E)=\frac{n(E)}{n(s)} \\P(E) =\frac{196125600}{886163135}\\\\ =0.22$