Question

In a class, there are 48 students.Among them,43 students were passed, then find the percentage of pass and fail of the class

Answer 1

Step-by-step explanation:

GIVEN

TOTAL NO OF STUDENTS:-48

TOTAL NO OF STUDENTS PASSED :-43

SO PERCENTAGE OF STUDENTS WHO PASSED -

43/48*100

• 89.53 %

and who failed will be 10.47%(100-89.53)

Answer 2

Answer:  The required pass and fail percentage of the class are 89.58% and 10.42% respectively.

Step-by-step explanation:  Given that in a class,  there are 48 students. Among them,43 students were passed.

We are to find the percentage of pass and fail of the class.

According to the given information, the number of students passed, n = 43 and the number of students failed, m = 48-43 = 5.

Therefore, the percentage of pass of the class is

$P_p=\dfrac{n}{48}\times100\%=\dfrac{43}{48}\times100\%=89.58\%$

and the percentage of fail of the class is

$P_f=\dfrac{m}{48}\times100\%=\dfrac{5}{48}\times100\%=10.42\%.$

Thus, the required pass and fail percentage of the class are 89.58% and 10.42% respectively.