In a class there are two sections i.e. A and B. 25% of the students in section A and 4414/99% of the students
in section B are girls. If two students are chosen at random one each from section A and section Bas class
representative then find the probability that there will be exactly one boy out of chosen two students?
1. 17/36
2.13/36
3.1/2 A
4.7/18
5.419
Answers
Given : numbers of Girls students in section A & section B and two students are chosen at random one from each section
To find : probability that there will be exactly one boy out of chosen two students
Solution:
in Section A 25% of students are girls
Girls = 25/100 = 1/4
Boys = 1 - 1/4 = 3/4
in Section B 4414/99% of the students are girls
Girls = 4414/9900 = 2207/4950
Boys = 1 - 2207/4950 = 2743/4950
the probability that there will be exactly one boy out of chosen two students
(3/4)(2207/4950) + (1/4)(2743/4950)
= 9364/ (4 * 4950)
= 2341/4950
= 0.473
With Correction in data 4400/99% of the students are girls
in Section A 25% of students are girls
Girls = 25/100 = 1/4
Boys = 1 - 1/4 = 3/4
in Section B 4400/99% of the students are girls
Girls = 4400/9900 = 4/9
Boys = 1 - 4/9 = 5/9
the probability that there will be exactly one boy out of chosen two students
(3/4)(4/9) + (1/4)(5/9)
= (12 + 5)/36
= 17/36
17/36 is the probability that there will be exactly one boy out of chosen two students
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