Math, asked by Muktidohare19, 3 months ago

in a classroom,5 friends are seated at the point A,B,C,D and E as shown in fig considering P as origin answer the following questions (i) the abcissa of point C is (a) 0 (b) 4 (c) 9 (d)1 (ii) (a)0,0 (b)1,1 (c)1,4 (d) 4,1 (iii) what was the coordinate of B if A is taken as the origin (a)0,0(b)3,4(c)3,3(d)4,3 (iv) what is the distance of AD (a)3 units (b)3√2 units (c)2√3 units (d) 4units​

Answers

Answered by vedantsah
0

Answer:

Answer in explanation. Please mark me as brainliast. Hope it helps.

Step-by-step explanation:

According to the fig. A(3,4),B(6,7),C(9,4) and D(6,1) are the position of 4 friends .

If we join all these points then

By using distance formula

=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

AB=

(3−6)

2

+(4−7)

2

=

(−3)

2

+(−3)

2

=

9+9

=

18

=3

2

BC=

(6−9)

2

+(7−4)

2

=

(−3)

2

+(3)

2

=

9+9

=

18

=3

2

CB=

(9−6)

2

+(4−1)

2

=

(3)

2

+(3

2

)

=

9+9

=

18

=3

2

AD=

(3−6)

3

+(4−1)

2

=

−3)

2

+(3)

2

=

9+9

=

18

=3

2

if we join the point AC and BD than

DiagonalAC=

(3−9)

2

+(4−4)

2

=

(−6)

2

+(0)

2

=

36

=6

Diagonal BD=

(6−6)

2

+(7−1)

2

=

(0)

2

+(6)

2

=

36

=6

Hence all the sides of a quadrilateral are the same and the diagonals are also the same so ABCD is a square.

Hence Champa is correct.

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