in a classroom,5 friends are seated at the point A,B,C,D and E as shown in fig considering P as origin answer the following questions (i) the abcissa of point C is (a) 0 (b) 4 (c) 9 (d)1 (ii) (a)0,0 (b)1,1 (c)1,4 (d) 4,1 (iii) what was the coordinate of B if A is taken as the origin (a)0,0(b)3,4(c)3,3(d)4,3 (iv) what is the distance of AD (a)3 units (b)3√2 units (c)2√3 units (d) 4units
Answers
Answer:
Answer in explanation. Please mark me as brainliast. Hope it helps.
Step-by-step explanation:
According to the fig. A(3,4),B(6,7),C(9,4) and D(6,1) are the position of 4 friends .
If we join all these points then
By using distance formula
=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
AB=
(3−6)
2
+(4−7)
2
=
(−3)
2
+(−3)
2
=
9+9
=
18
=3
2
BC=
(6−9)
2
+(7−4)
2
=
(−3)
2
+(3)
2
=
9+9
=
18
=3
2
CB=
(9−6)
2
+(4−1)
2
=
(3)
2
+(3
2
)
=
9+9
=
18
=3
2
AD=
(3−6)
3
+(4−1)
2
=
−3)
2
+(3)
2
=
9+9
=
18
=3
2
if we join the point AC and BD than
DiagonalAC=
(3−9)
2
+(4−4)
2
=
(−6)
2
+(0)
2
=
36
=6
Diagonal BD=
(6−6)
2
+(7−1)
2
=
(0)
2
+(6)
2
=
36
=6
Hence all the sides of a quadrilateral are the same and the diagonals are also the same so ABCD is a square.
Hence Champa is correct.