Math, asked by rejanirejithlal, 5 hours ago

In a classroom activity on real numbers, the students have to pick a number card from a

pile and frame a question on it if it is not a rational number for the rest of the class. The

number cards picked up by first 5 students and their questions on the numbers for the rest

of the class are as shown below. Answer them.

Questions 41- 45 are based on Case Study 1

41 Suraj picked up √8 and his question was: Which of the following is true about √8 ?

(a) It is a natural number

(b) It is an irrational number

(c) It is a rational number

(d) None of these

42 Shreya picked up ‘BONUS’ and her question was: Which of the following is not

irrational?

(a) 3-4√5

(b) √7 -6

(c) 2 +2√9

(d) 4√11 – 6

43 Ananya picked up √15−√10 and her question was: √15−√10 is ____ number.

(a) a natural

(b) an irrational

(c) a whole

(d) a rational

44 Suman picked up 1/√5 and her question was: 1/√5 is _______ number.

(a) a whole

(b) a rational

(c) an irrational

(d) a natural

45 Preethi picked up √6and her question was: Which of the following is not irrational?

(a) 15 +3 √6

(b) √24 -9

(c) 5√150

(d) None of these​

Answers

Answered by Anonymous
19

Step-by-step explanation:

41.(b)

42.(c)

43.(b)

44.(c)

45.(d)

Mark me the brainliest

Answered by NirmalPandya
24

Answer:

The answers to the questions are as follows:

41. Option (b) It is an irrational number

Because it cannot be expressed in the ratio \frac{p}{q}, \sqrt{8} is definitely not a rational number and also not a natural number.

42. Option (c) 2+2\sqrt{9}

2+2\sqrt{9} can be written as 2 + (2×±3) because \sqrt{9}= ±3

2+2\sqrt{9}=2+(2*3) or 2+(2*(-3))=2+6 or 2-6=8 or 4 either of which are rational numbers. Other options are not suitable because they're clearly irrational numbers.

43. Option (b) an irrational

\sqrt{15} -\sqrt{10}=\sqrt{5} Difference/sum of two irrational numbers is an irrational number. Here, the difference obtained is \sqrt{5} which is an irrational number. So, the correct answer is (b).

44. Option (c) an irrational

\frac{1}{\sqrt{5} } an irrational number because though it looks like it is in the form  \frac{p}{q}, it is not. p and q should be integers. \sqrt{5} is not an integer, it's irrational. Hence, \frac{1}{\sqrt{5} } is irrational.

45. Option (d) None of these

None of the options provided is a rational number because all of them are irrational.

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