In a closed circuit of resistance 10Ω, the linked flux varies with time according to relation ϕ=6.t2-5t+1.At t=0.25 second, the current (in Ampere) flowing through the circuit is
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I tried using two different methods and my answer is 0.2A
But since the answer in my books is given 1.2A can anybody confirm and tell me know.
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