Physics, asked by ananyasinha4967, 10 months ago

In a closed circuit the current I (in ampere) at an instant of time t (in second) is given by I= 4-0.08t. The number of electron flowing in 50 sec through the cross- section of the conductor is

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Answered by mvm9363

Answer:

In a closed circuit, the current / (in ampere) at an instant of time t (in second) is given by l = 4-0.08t. The number of electrons flowing in 50 s through the cross-section of the conductor is

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