Question

In a closed system:A(s)⇌2B(g)+3C(g) if the partial pressure of C is doubled then partial pressure of B will be??

Answer 1

for the closed system :A(s)⇌2B(g)+3C(g) 
kp=(pB)^2  *(pC)^3
⇌kp/(pC)^2=(pB)^2.......equation 1 
since kPis constant we double the partial pressure of C then pC= 2pC
than you'd have a few steps solving and your answer would be 


thus pressure of B component will reduce by a factor of 2, square root of 2 

Answer 2

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Kashif Yusuf asked in Chemistry

In a closed system:A(s)⇌2B(g)+3C(g) if the partial pressure of C is doubled then partial pressure of B will be??

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Shikha Aggarwal answered this
1520 helpful votes in Chemistry, Class XII-Science

 For the closed system :

A(s)  2B (g) + 3C(g) 

   Kp = (pB)2 × (pC)3
⇒Kp(pC)3= (pB)2       ............ equation 1

since Kp is constant thus if we double the partial pressure of C then p'C = 2pC
   Kp = (p'B)2 ×( p'C)3
   Kp = (p'B)2 × (2pC)3
     Kp(2pC)3= (p'B)2  Kp 8 (pC)3= (p'B)2  From equation 118 (pB)2   = (p'B)2   p'B = 122√ pBThus pressure of B component will reduce by a factor of 22√.