Question

In a closed vessel. an ideal gas at 1 atm is heated from 27 °C to 327 °C. The final
pressure of the gas will approximately be​

Answer 1

hope this will help you

Answer 2

The final pressure is 2 atm.

Explanation:

We have: Volume is constant, since vessel is closed

Let us assume that the gas is ideal.

i.e, it obeys PV = nRT

where,

P= pressure

V= volume of gas

n= number of moles

R= universal gas constant

T= temperature in kelvin.

since V, R, n don't change,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

T₁ =27+273 = 300K

T₂=327+273= 600K

i.e, P₂= P₁($\frac{600}{300}$)

= 1(2) = 2 atm.

Therefore the final pressure = 2 atm.