Math, asked by priya1828, 1 year ago


In a coal mine an elevator takes the miner into the mine at the rate of 10m per minute. If it begins
to descend from a point 25 meters above the ground what will be its position after 25 minutes?​

Answers

Answered by jassmanak9398
0

Answer:

hello

Step-by-step explanation:

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,The elevator has to travel 10m till the ground, then 350 m more.

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,The elevator has to travel 10m till the ground, then 350 m more.So, the total distance to travel is 360 m

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,The elevator has to travel 10m till the ground, then 350 m more.So, the total distance to travel is 360 mIf the elevator's speed is 6 metres/minute,

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,The elevator has to travel 10m till the ground, then 350 m more.So, the total distance to travel is 360 mIf the elevator's speed is 6 metres/minute,Then

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,The elevator has to travel 10m till the ground, then 350 m more.So, the total distance to travel is 360 mIf the elevator's speed is 6 metres/minute,ThenTime= Distance/Speed

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,The elevator has to travel 10m till the ground, then 350 m more.So, the total distance to travel is 360 mIf the elevator's speed is 6 metres/minute,ThenTime= Distance/Speed        = 360/6

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,The elevator has to travel 10m till the ground, then 350 m more.So, the total distance to travel is 360 mIf the elevator's speed is 6 metres/minute,ThenTime= Distance/Speed        = 360/6        =60 minutes

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,The elevator has to travel 10m till the ground, then 350 m more.So, the total distance to travel is 360 mIf the elevator's speed is 6 metres/minute,ThenTime= Distance/Speed        = 360/6        =60 minutes        =1 hour

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,The elevator has to travel 10m till the ground, then 350 m more.So, the total distance to travel is 360 mIf the elevator's speed is 6 metres/minute,ThenTime= Distance/Speed        = 360/6        =60 minutes        =1 hourThus the elevator would take 1 hour to reach its destination.

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