Question

In a coil there was 61/2m of wire. Two pieces of 16/3m and 13/2m in length were cut out. What length of wire is left in the coil now?​

Answer 1

Answer:

56/3

Step-by-step explanation:

$\frac{61}{2} = \frac{16}{3} + \frac{13}{2} + x$

$= > \: x = \frac{56}{3}$