Question

In a coil when current changes from 10a to 2a in time 0.1 s, induced emf is 3.28v. What is the self inductance of coil

Answer 1

Answer:

According to Faraday's Law:

⇒ Induced Emf = L × di/dt

Here, L refers to Self Inductance of the coil.

According to the question,

• EMF = 3.28 V
• di/dt = 10-2/0.1 = 8/0.1 = 80 A/s

Substituting the values we get,

⇒ 3.28 V = L × 80 A/s

⇒ L = 3.28 V / 80 A/s

⇒ L = 0.041 or 4.1 × 10⁻² H

This is the required answer.

Hope it helped !!