In a coin box 50-paisa coins and 1 rupee coins are in the ratio of 2:5 respectively. If the average number of coins are 140, calculate 1 rupee coins in the box (a) 70 (b) 100 (c) 200 (d) 210 The individual weights (in kg) of six of them are 52.57
Answers
Answer:
option c
Step-by-step explanation:
Coins in the box = 50P and Rs.1
The average no of coins = 140
• Ratio of the coins = 2:5
To Find :
The number of Rs.1 coins = ?
Solution :
• To calculate the number of coins at first we have to assume the the number of coins be x. As per the given clue in question we have to solve the value for x then calculate the number of Rs.1 coin.
Given ratio of the coins :
For 50P co
For Rs.1 coins = 5
As per the ratio of coins the no :
No of Rs.1 coins = 5x => 5x
No of 50P coins = 2x => 2x
As per setting up equation :
→ sum of coins/2 = Average of coins
⇒Rs.1 + 50P/2 = 140
⇒5x + 2x/2 = 140
⇒7x = 140 × 2
⇒7x = 280
⇒x=40
Hence,
The number of Rs.1 coins (5x) = 5(40) = 200
Answer:
Answer:
option c
Step-by-step explanation:
Coins in the box = 50P and Rs.1
The average no of coins = 140
• Ratio of the coins = 2:5
To Find :
The number of Rs.1 coins = ?
Solution :
• To calculate the number of coins at first we have to assume the the number of coins be x. As per the given clue in question we have to solve the value for x then calculate the number of Rs.1 coin.
Given ratio of the coins :
For 50P co
For Rs.1 coins = 5
As per the ratio of coins the no :
No of Rs.1 coins = 5x => 5x
No of 50P coins = 2x => 2x
As per setting up equation :
→ sum of coins/2 = Average of coins
⇒Rs.1 + 50P/2 = 140
⇒5x + 2x/2 = 140
⇒7x = 140 × 2
⇒7x = 280
⇒x=40
Hence,
The number of Rs.1 coins (5x) = 5(40) = 200
ANSWER