Question

In a college, 60 students enrolled in chemistry,40 in
physics, 30 in biology, 15 in chemistry and physics, 10
in physics and biology, 5 in biology and chemistry. No
one enrolled in all the three. Find how many are
enrolled in at least one of the subjects.​

Answer 1

Answer:

45 are enrolled in biology.

Step-by-step explanation:

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Answer 2

➠Solution:-

Let C, P and B represents the subjects Chemistry, Physics  and Biology respectively.

⇒Number of students enrolled in Chemistry :

n(C)  =  60

⇒Number of students enrolled in Physics :

n(P)  =  40

⇒Number of students enrolled in Biology :

n(B)  =  30

⇒No.of students enrolled in Chemistry and Physics :

n(CnP)  =  15

⇒No.of students enrolled in Physics and Biology :

n(PnB)  =  10

⇒No. of students enrolled in Biology and Chemistry :

n(BnC)  =  5

⇒No one enrolled in all the three. So, we have

n(CnPnB)  =  0

The above information can be put in a venn diagram as shown below. 

From, the above venn diagram, number of students enrolled in at least one of the subjects :

=  40 + 15 + 15 + 15 + 5 + 10 + 0

=  100

So, the number of students enrolled in at least one of the subjects is 100.