Math, asked by vimaljain, 1 year ago

In a colony 6÷8 of the total people were females. if the number of females is 36 more than that of the males how many males were there in the colony.


vimaljain: please help me please

Answers

Answered by foradityamp96pjw
30
Hey dear


here is your answer


Solution


Let the total number of people be x

No of female = 6x / 8


So

No of male = total people - number of female

So , = x - 6x /8

= < take Lcm 8 >

= x * 8 / 1*8 - 6x /8

= 8x / 8 - 6x /8

no of male = 2x / 8


According to the question


6x / 8 = 36 + 2x /8

6x /8 - 2x / 8 = 36

4x / 8 = 36

x = 36 *8 /4

simplify this

it comes 72


hence no of male is

2/8 *72. ,( simplify this)

= 18


hence your answer is



< no of male is 18 >




hope it helps

thank you


vimaljain: thanks I like your solution
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