Math, asked by sania703, 1 year ago

in a Colony 6 upon 8 of the total people were females. If the number of females is 36 more than of the males how many males were in the colony​?

Answers

Answered by TooFree
34

Answer:

18

Step-by-step explanation:

Given that females = 6/8

Find the fraction of males:

Males = 1 - 6/8 = 2/8

Given that there are 36 more females than males:

6/8 - 2/8 = 36

4/8 of the colony = 36

2/8 of the colony = 36 ÷ 2 = 18

Answer: 18 of the colony are males.


sania703: very good your answer is totally right
ouytt: welcome..!
sania703: keep it up
sahil168243: thanks bro
Answered by ouytt
10

Answer:

Step-by-step explanation:

Let total no. of people be x

So 6/8 of x = 36

6x = 8 × 36

6x = 288

x = 48

So there are total 48 people in the society.

it is already given that 36 are females

so No. of males are 48 - 36 = 12

So there are 12 male members in the society.

Hope it helps you.


sania703: wrong
sania703: but good for trying
ouytt: okk
Answered by Swayze
19

Hi

Its swayze (luv)

___________________________

Here is your answer

___________________________

= 6/8 of total people were females.

So males = 2/8..

Ratio concept

Total people = 8 parts, 6 parts F & 2 parts M]

Females : Males = 6/8 : 2/8 = 6:2

_______Given________

Females are 36 more than males.

Hence ratio difference is given as '36'

(6-2)-- 4 parts===36

1 part== 36/4 = 9

2 parts(M)== 2*9 = 18

Hence, number of males is '18'

________________________

Hope it helps

Thankyou


sania703: good thanks
Swayze: : )
Swayze: Welcome
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