Question

In a combined test in maths and Chemistry ; 84% candidates passed in maths ; 76% in chemistry and 8% failed in both find the percentage of failed candidates if 340 candidates passed in the test ; then how many appeared

Answer 1

Solution :-

Given :

84 % candidates passed in maths

76 % candidates passed in chemistry

8 % candidates failed in both the subjects.

So, 92 % candidates passed in at least one subject.

Let us assume that x % candidates passed in the test.

Therefore,

84 + 76 - x = 92

⇒ - x = 92 - 160

⇒ - x = - 68 

⇒ x = 68

So, 68 % candidates passed in the test or both the subjects.

Given that 340 candidates passed in the test.

Therefore, total number of candidates appeared = (340*100)/68

= 500 candidates.

Hence, 500 candidates appeared in the test.

Failed in both the subjects = (500*8)/100 = 40 candidates

Passed in maths = (500*84)/100 = 420 candidates

Passed in chemistry = (500*76)/100 = 380 candidates

Answer.

Answer 2

Answer:

Step-by-step explanation:

Given,

84% candidates passed in maths.

76% candidates passed in Chemistry.

8% candidates failed in both the subjects.

So,92% candidates passed  atleast in one subject.

Let us assume that x%  candidates passed in the test.

Therefore,

84 + 76 - x =92

= -x= 92= 160

= -x = -68.

= 68

So,68% candidates passed in the test or both the subjects.

Given that 340 candidates passed in the test.

Therefore,total number of candidates appeared = (340*100)/68.

=500 candidates

Hence,500 candidates appeared in the test.

Failed in both subjects = (500*8)/100=40 candidates.

Passed in maths =(500*84)/100=420 candidates.

Passed in chemistry = (500*76)100=380 candidates

Answer.